Question

如图,以线段AB为直径的○O交线段AC于点E,点OM垂直于AE交AE于点D,∠BOE=60°,∠C=60°,BC=2根号

Answer 1

首先可以的得出AB = 6,所以圆的半径为3,

A0 = OM = OE = OB = 3.

∠A = 30°,OD = 3/2,AD = 3根号3/2

所以AM = 3,所以△AMO为等边,所以∠AOE = 60°

同理△OME为等边,ME = 3.