(1)原式= x 2+2 x +1- x 2+2 x
=4 x +1
(2)原式= a·(-a 3)÷a 4
=-a 4÷a 4
=-1
(3)原式=(10y 2-3 x y)÷(-4 y)
=
x -
y (4)原式=2008×(2005 2-1-2005 2)
=-2008
(1)原式= x 2+2 x +1- x 2+2 x
=4 x +1
(2)原式= a·(-a 3)÷a 4
=-a 4÷a 4
=-1
(3)原式=(10y 2-3 x y)÷(-4 y)
=
x -
y (4)原式=2008×(2005 2-1-2005 2)
=-2008