Z=z(x+y),sin(x+y)+ez=0,求dz/dx
1个回答
dsin(x+y)+de^z=0
cos(x+y)(dx+dy)+e^zdz=0
dz=-e^{-z}cos(x+y)(dx+dy)
所以dz/dx=-e^{-z}cos(x+y)
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