Question

计算：(3x四次方y+2x²y²)÷(二分之一x)×(2x负一次方）

Answer 1

[3(x^4)y+2(x^2)(y^2)]/(x/2)*(2/x)

=3(x^4)y+2(x^2)(y^2)]*[4/(x^2)]

=12(x^2)y+8y^2