[x(x²y²-xy)-2y(x²-x³y)÷3x²y
1个回答
[x(x²y²-xy)-2y(x²-x³y)]÷3x²y
= (1/3)[(xy-1)-2(1-xy)]
= xy-1
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(x²y³+xy)(x²y³-xy)÷x²y³,其中x=3,
已知x÷y=3,则x²+2xy-3y²÷(x²-xy+y²)=?