Question

BE是∠ABC的平分线,AD‖BC交BE与D.已知∠ADE=155°,求∠BAD的度数.

Answer 1

∠ABD = ∠CBD = ∠ADB = 180°-∠ADE = 180°-155° = 25° ,

∠ABC = ∠ABD+∠CBD = 25°+25° = 50° ,

∠BAD = 180°-∠ABC = 180°-50° = 130° .