Question

（x的平方-9）分之（x-4）乘以{1+（x的平方-8x+16分之10x-19}除以{（x减3 ）分之1}

Answer 1

（x的平方-9）分之（x-4）乘以{1+（x的平方-8x+16分之10x-19}除以{（x减3 ）分之1}

=（x-4)/[(x+3)(x-3)]{1+（10x-19)/[(x-4)^2]}*(x-3)

=1/(x+3){x^2-2x-3}/（x-4)

= (x^2-2x-3)/(x^-x-12)