(x-4)(x-6)+1
=x^2-10x+25
=(x-5)^2 ^2为平方
(a+b)²+4(a+b+1)
=(a+b)^2+4(a+b)+4
=(a+b+2)^2
a²+b²+4a-2b+5=0
(a+2)^2+(b-1)^2=0
a=-2 b=1
(x-4)(x-6)+1
=x^2-10x+25
=(x-5)^2 ^2为平方
(a+b)²+4(a+b+1)
=(a+b)^2+4(a+b)+4
=(a+b+2)^2
a²+b²+4a-2b+5=0
(a+2)^2+(b-1)^2=0
a=-2 b=1