Question

(x-2)的平方 分之x+3=x-2分之A+(x-2)的平方分之B

Answer 1

(x+3)/(x-2)²≡A/(x-2)+B/(x-2)²,部分分式

(x+3)/(x-2)²=[A(x-2)+B]/(x-2)²

x+3=A(x-2)+B

当x=2,

5=B

当x=0

3=A(-2)+5

-2=A(-2)

A=1

∴(x+3)/(x-2)²=1/(x-2)+5/(x-2)²