Question

(a^2+1)(-4a^2+1)+a^4-1 3a(a-b)(a+b)-6(b-a)^2

Answer 1

(a^2+1)(-4a^2+1)+a^4-1

=(a^2+1)(-4a^2+1)+(a^2+1)(a^2-1)

=(a^2+1)(-4a^2+1+a^2-1)

=-3a^2(a^2+1)

3a(a-b)(a+b)-6(b-a)^2

=3a(a-b)(a+b)-6(a-b)^2

=3(a-b)(a^2+ab-2a+2b)

a^2-9(a-b)^2

=a^2-(3a-3b)^2

=(a+3a-3b)(a-3a+3b)

=(4a-3b)(3b-2a)