f(0)=1/2+b=1, b=1/2
f(π/2)=1/2+c=1, c=1/2
f(x)=1/2+1/2 cosx + 1/2 sinx = 1/2 + (根号2/2)sin(x+π/4)
因为周期T=2π, 所以对称轴之间最短距离为π
先求sin(x+π/4)的最小值,当x+π/4∈[π/4,3π/4], sin(x+π/4)最小为根号2/2
所以f(x)最小为1/2+根号2/2*根号2/2=1
f(0)=1/2+b=1, b=1/2
f(π/2)=1/2+c=1, c=1/2
f(x)=1/2+1/2 cosx + 1/2 sinx = 1/2 + (根号2/2)sin(x+π/4)
因为周期T=2π, 所以对称轴之间最短距离为π
先求sin(x+π/4)的最小值,当x+π/4∈[π/4,3π/4], sin(x+π/4)最小为根号2/2
所以f(x)最小为1/2+根号2/2*根号2/2=1