Question

甲容器中有8%的盐水300克,乙容器中有12.5%的盐水120克,往甲、乙两个容器中分别倒入等量的水,使两个容器

Answer 1

设每个容器倒入 x 克水,则

300·8%/(300 + x) = 120·12.5%/(120 + x)

24/(300 + x) = 15/(120 + x)

8(120 + x) = 5(300 + x)

960 + 8x = 1500 + 5x

3x = 540

x = 180

答：每个容器倒入 180 克水.