√2/4sin(π/4-x)+√6/4cos(π/4-x)
=√2/2[sin(π/4-x)*1/2+cos(π/4-x)*√3/2]
=√2/2[sin(π/4-x)cosπ/3+cos(π/4-x)sinπ/3]
=√2/2sin(π/4-x+π/3)
=√2/2sin(7π/12-x)
=√2/2sin(π/2+π/12-x)
=√2/2cos(π/12-x)
=√2/2cos(x-π/12)
化简 √2/4sin(π/4-x)+√6/4cos(π/4-x)
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