解
4-x=2(-0.5x²+2.5x-2)
4-x=-x²+5x-4
x²-6x+8=0
(x-4)(x-2)=0
∴x=4或x=2
4-x=2(-0.5x²+2.5x-2)
3个回答
相关问题
-
5(2-x)=-(2x-7) 0.5x-2=0.8(2x-1.5) 2(x+0.5)-3(x-0.4)=5.6
-
f(x)=(x^2-2x)^0.5+2^[(x^2-5x+4)^0.5]的值域?
-
2x-0.8×2.6=3.08-2x 2.4×0.2x=0.5x-2.4 5(0.2x-2.5)=2.1x
-
2x-0.8×2.6=3.08-2x 2.4×0.2x=0.5x-2.4 5(0.2x-2.5)=2.1x
-
2.X(2X-5)=4X-10 2X^2-9X+10=0 (2X-5)(X-2)=0 X1=2.5,X2=2
-
X1 - X3 - X4 -5X5=0 X1+2X2+3X3+3X4+7X5=0 X1+X2+X3+X4+X5=0 X2
-
x²--5x--2=0 9(2x+3)²--4(2x--5)²=0 (6x²--
-
x^2+y^2-4*x-5=0 (x-1)^2+(y-2)^2=4 (2-x)^2+(4-y)^2-4*x-5=0 根据
-
1）4x2-12x-1=0 （2）3x2+2x-3=0 （3）5x2-4x-12=0 （4）3x(x+2)=5(x+2)
-
不等式(2x-0.5)/0.5-(2x-1.4)/0.2>(0.5-x)/0.25