x²+4x+y²-2y+5=0
x²+4x+4+y²-2y+1=0
(x+2)²+(y-1)²=0
x+2=0 x=-2
y-1=0 y=1
x²+y²=(-2)²+1²=5
已知xx+4x+yy-2y+5=0,则xx+yy=
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