a,b互为相反数,则 a+b=0
c,d互为倒数,则cd=1
|x|=3,则 x=3 或 x=-3
当x=3时:
|x|-(a+b+cd分之1)x-cd
=3-1×3-1
=3-3-1
=-1
当x=-3时:
|x|-(a+b+cd分之1)x-cd
=3-1×(-3)-1
=3+3-1
=5
解补充题:
原式=7.41×(-5/13)-3×5/13+0.51×5/13
=-7.41×5/13-3×5/13+0.51×5/13
=(-7.41-3+0.51)×5/13
=-(7.41+3-0.51)×5/13
=-9.9×5/13
=-99/10×5/13
=-99/26