an=Sn-1 +2^n=Sn-S(n-1)
2Sn-1+2^n+2^n=Sn+2^n
2(Sn-1+2^n)=Sn+2^n
则Sn+2^n为等比数列,S1+2^1=5
则Sn+2^n=5*2^(n-1)
Sn=3*2^(n-1)
当n>1时,an=Sn-Sn-1=3*2^(n-2),a1=3
答:当n>1时,an=Sn-Sn-1=3*2^(n-2),a1=3
Sn=3*2^(n-1)
an=Sn-1 +2^n=Sn-S(n-1)
2Sn-1+2^n+2^n=Sn+2^n
2(Sn-1+2^n)=Sn+2^n
则Sn+2^n为等比数列,S1+2^1=5
则Sn+2^n=5*2^(n-1)
Sn=3*2^(n-1)
当n>1时,an=Sn-Sn-1=3*2^(n-2),a1=3
答:当n>1时,an=Sn-Sn-1=3*2^(n-2),a1=3
Sn=3*2^(n-1)