Question

已知x,y,z成等差数列 求证:x2[y+z],y2[x+z],z2[x+y]成等差数列

Answer 1

由x,y,z成等差数列,得x+z=2y

x^2(y+z)+z^2(x+y)=y(x^2+z^2)+xz(x+z)

=y((x+z)^2-2xz)+xz(x+z)

=y(4y^2-2xz)+2xyz

=4y^3-2xyz+2xyz

=4y^3

y^2(x+z)=y^2*2y=2y^3

所以,x^2(y+z)+z^2(x+y)=2y^2(x+z),即x^2[y+z],y^2[x+z],z^2[x+y]成等差数列