Question

0 1 1 1 1……11 0 1 1 1……11 1 0 1 1……11 1 1 0 1……1•̶

Answer 1

D=(n-1)乘以-1的(n-1)次方

将第一列*（-1）分别加到后面各列,得

0 1 1 1 1... 1 1

1 -1 0 0 0... 0 0

1 0 -1 0 0... 0 0

1 0 0 -1 0... 0 0

1 0 0 0 -1... 0 0

.

1 0 0 0 0...-1 0

1 0 0 0 0... 0 -1

再将第2至第n行分别加到第1行,得

n-1 0 0 0 0... 0 0

1 -1 0 0 0... 0 0

1 0 -1 0 0... 0 0

1 0 0 -1 0... 0 0

1 0 0 0 -1... 0 0

.

1 0 0 0 0...-1 0

1 0 0 0 0... 0 -1

所以,D=(n-1)乘以-1的(n-1)次方