Question

limx-0(1-3根号1-x+x^2)/x

Answer 1

x→0时[1-3√(1-x+x^2)]/x不存在,

[1-(1-x+x^2)^(1/3)]/x

=(1-x)/[1+(1-x+x^2)+(1-x+x^2)^(2/3)]（分子有理化）

→1/3.