Question

分式通分,求你们了1.x-1/x的2次方+1?5/6xy的4次方 2.x+4/x^2-8x+15?x+5/x^2+x-1

Answer 1

1.

(x- 1)/(x^2 +1)

=6xy^4(x-1)/6xy^4(x^2+1)

5/6xy^4

=5(x^2+1)/6xy^4(x^2+1)

2.

(x+4)/(x^2-8x+15)

=(x+4)/(x-3)(x-5)

=(x+4)^2/(x-3)(x-5)(x+4)

(x+5)/(x^2+x-12)

=(x+5)/(x-3)(x+4)

=(x+5)(x-5)/(x-3)(x+4)(x-5)

(x-3)/(x^2-x-20)

=(x-3)/(x+4)(x-5)

=(x-3)^2/(x-3)(x+4)(x-5)