2^(xy) = x + y,当x=0时,y = 1
(xy)ln2 = ln(x+y)
两边微分得:
(ydx + xdy)ln2 = (dx+dy)(x+y)
代入x=0,y=1 得
ln2dx = dx+dy
所以,dy = (ln2 - 1)dx
2^(xy) = x + y,当x=0时,y = 1
(xy)ln2 = ln(x+y)
两边微分得:
(ydx + xdy)ln2 = (dx+dy)(x+y)
代入x=0,y=1 得
ln2dx = dx+dy
所以,dy = (ln2 - 1)dx