∠D与∠A的关系是 ∠A =2∠D.
延长BC至E
∵CD是∠ACB的外角平分线,AD是∠ABC的平分线
∴∠DCE=1/2∠ACE,∠DBC=1/2∠ABC
∵∠DCE=∠DBC+∠D
∠ACE=∠ABC+∠A ①
∴ 1/2∠ACE=1/2∠ABC+∠D
∴ ∠ACE=∠ABC+2∠D ②
由①②得 ∠ABC+∠A =∠ABC+2∠D
∴∠A =2∠D
∠D与∠A的关系是 ∠A =2∠D.
延长BC至E
∵CD是∠ACB的外角平分线,AD是∠ABC的平分线
∴∠DCE=1/2∠ACE,∠DBC=1/2∠ABC
∵∠DCE=∠DBC+∠D
∠ACE=∠ABC+∠A ①
∴ 1/2∠ACE=1/2∠ABC+∠D
∴ ∠ACE=∠ABC+2∠D ②
由①②得 ∠ABC+∠A =∠ABC+2∠D
∴∠A =2∠D