(x+5y)^+(2x+10y)(3x-y)+(3x-y)^
1个回答
(x+5y)^+(2x+10y)(3x-y)+(3x-y)^
=(x+5y)^+2(x+5y)(3x-y)+(3x-y)^
=[(x+5y)+(3x-y)]^
=(4x+4y)^
=16(x+y)^
相关问题
(x+5y)²-(2x+10y)(3x-y)+(3x-y)²
5x^3y(x-y)^3-10x^4y^3(y-x)^2
5X^3Y(X-Y)-10X^4Y^3(Y-X)^2
3x+4y+10=3.5(x+y+2) 0+2+14+3x+4y=2.5(10+x+y)
1.8x+5y=10 8x-5y=10 2.3x+2y=9 4x-2y=5 3.2x+3y=5 6x-2y=-6 4.3
(-2x^4y^5)^3 (-3x^3y^)^/(-12x^10y^10)
(4.5*10^5)(2*10^3)(3*10^4)&2x^2y(-8y^2)+4x^2y*5y^2&(x+3y)(2x
解二元一次方程1.x+y=3 2.x-y=-5 3.x=3y 4.4x-3y=17 5.3x+y=10 x-y=2 3x
{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3
2X=3Y,4x-5y=2 -6x+5y=3,3x=4y 2x+3y=5,3x=y-9 3x=1-y,3x=2y-5