设x+y=2根号3,则m=x^2+2y^2=?
2个回答
y=2根号3-x
则m=x^2+2(2根号3-x)^2
=3x^2-8根号3x+24
=3(x-4根号3/3)^2+8
故最小值为8 此时x=4根号3/3 y=2根号3/3
相关问题
设M={x|y=根号(x+2)},N={x︳y=根号(-2x+8)},则M∩N=
设集合M={(x,y)|(x-根号3)^2+y^2
设M={y|y=3-x^2,x属于R},N={x|y=根号x-3}则M交N
设集合M={y|y=3-x2},N={y|y=2x2-1},则M∩N=______.
设集合M={y|y=3-x2},N={y|y=2x2-1},则M∩N=______.
1.设集合M={y|y=3-x^2},N={y|y=2x^2-1}则M∩N=
根号2-x+根号x-2+y=3成立,则x^y=
设A{(x,y)|y=根号(2a^2-x^2),a>0},B={(x,y)|(x-1)^2+(y-根号3)^2=a^2,
根号2x+3y-m-6 + 根号x+2y+m-5=根号x+y-3 * 根号3-y-x ,试求m的值.
x,y为有理数,设9-(根号2)x-根号2=x+3y-(根号2)y-根号8,求(x-y)^2010的值