原式=[(a+b)(a-b)/ab(a+b)]÷[-(a²-2ab+b²)/2ab]
=[(a-b)/ab]÷[-(a-b)²/2ab]
=-[(a-b)/ab]×[2ab/(a-b)²]
=-2ab(a-b)/[ab(a-b)²]
=-2/(a-b)
帮忙化简下a² -b²/a²b+ab²÷（1-a ² +b²
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