Question

[m(mn^3)^2-2(mn^2)^3-1]·(m^2n)^3

Answer 1

[m(mn^3)^2-2(mn^2)^3-1]·(m^2n)^3

=[m(m^2n^6)-2(m^3n^6)-1]·(m^6n^3)

=[m^3n^6-2m^3n^6-1]·(m^6n^3)

=[-m^3n^6-1]·(m^6n^3)

=-m^9n^9-m^6n^3