Question

（x^2- 3x+3)^2 - 3(x^2- 3x+3)+3=x

Answer 1

（x^2- 3x+3)^2 - 3(x^2- 3x+3)+3=x

（x^2- 3x+3)^2 - 3(x^2- 3x+3)+2=x-1

(x^2- 3x+3-1)(x^2- 3x+3-2)=x-1

(x-1)(x-2)(x^2- 3x+1)=x-1

(x-1)[(x^2- 3x+2-1)(x-2)-1]=0

(x-1)[(x-2)(x-2)(x-1)-x+1]=0

(x-1)(x-1)(x^2-4x+3)=0 即(x-1)^3(x-3)=0

解得x=1或x=3