Question

f(Ø)=1/2tan((π/2)Ø-5π/4)

Answer 1

T=2π/w

=π/（π/2）

=2

φ=5π/4

定义域 (π/2)Ø-5π/4≠π/2+kπ

(π/2)Ø≠7π/4+kπ

Ø≠7/2+k

值域为R

令Ø=0 1/2 tan(5π/4)=（1/2）*（-1）

=-1/2

令y=0 1/2tan((π/2)Ø-5π/4)=0

(π/2)Ø-5π/4= kπ k∈Z

(π/2)Ø= kπ+5π/4

Ø= k+ 5/2

渐近线的方程 (π/2)Ø-5π/4)= π/2+ kπ k∈Z

(π/2)Ø=7π/4+ kπ

Ø=7/2+ 2k