Question

已知动点P（x,y）满足根号下(x-1)^2+y^2=/x+y/,则P的轨迹

Answer 1

根号下(x-1)^2+y^2=/x+y/；

(x-1)^2+y^2=(x+y)^2;

x^2-2x+1+y^2=x^2+2xy+y^2;

2xy=1-2x;

y=1/2x-1

所以,p是双曲线y=1/2x,向下平移一个单位的图形