直线方程带入抛物线得k²x²+(2k²+1)x+k²=0
∴x1+x2=-(2k²+1)/k²
x1x2 =1
向量OA*向量OB=x1x2+y1y2=x1x2+k(x1+1)*k(x2+1)
=x1x2+k²(x1x2+x1+x2+1)
=1+k²(1-(2k²+1)/k² +1)
=1-1=0
∴OA⊥OB
直线方程带入抛物线得k²x²+(2k²+1)x+k²=0
∴x1+x2=-(2k²+1)/k²
x1x2 =1
向量OA*向量OB=x1x2+y1y2=x1x2+k(x1+1)*k(x2+1)
=x1x2+k²(x1x2+x1+x2+1)
=1+k²(1-(2k²+1)/k² +1)
=1-1=0
∴OA⊥OB