设至少有X本,则(x-3)能被6整除,(x-2)能被7整除,(x-9)能被11整除.
令(x-3)/6=a,则x=6a+3
令(x-2)=6a+3-2=6a+1=7b,
(x-9)=6a+3-9=6a-6=6a+1-7=7b-7=11c
a=1,b=1,c=0时,
x=9为最少
设至少有X本,则(x-3)能被6整除,(x-2)能被7整除,(x-9)能被11整除.
令(x-3)/6=a,则x=6a+3
令(x-2)=6a+3-2=6a+1=7b,
(x-9)=6a+3-9=6a-6=6a+1-7=7b-7=11c
a=1,b=1,c=0时,
x=9为最少