若f'(0)=2,求lim(h→0)f(x0-h)-f(x0)/2h的值
1个回答
lim(h→0)f(x0-h)-f(x0)/2h
=lim(h→0)(-1/2)*[f(x0)-f(x0-h)/h]
=(-1/2)*f'(0)
= -1
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