y=x-2与y轴交于(0,-2)
y=x-2与y=√x交于(4,2)
所以面积=∫【-2,2】(y+2)dy-∫【0,2】(y^2)dy
=(y^2/2+2y)【-2,2】-(y^3/3)【0,2】
=(2+4-2+4)-(8/3-0)
=8-8/3
=16/3
y=根号x与y=x-2及y轴围成图形的面积
y=x-2与y轴交于(0,-2)
y=x-2与y=√x交于(4,2)
所以面积=∫【-2,2】(y+2)dy-∫【0,2】(y^2)dy
=(y^2/2+2y)【-2,2】-(y^3/3)【0,2】
=(2+4-2+4)-(8/3-0)
=8-8/3
=16/3