解 由条件得(3b+2)²=0
3b+2=0
b=-2/3
4a+3b=0
4a-2=0
a=1/2
2(2a+3b)²-3(2a+3b)+8(2a+3b)²-7(2a+3b)
=10(2a+3b)²-10(2a+3b)
将a=1/2,b=-2/3代入原式中,得
=10(1-2)²+10(1-2)
=10-10
=0
解 由条件得(3b+2)²=0
3b+2=0
b=-2/3
4a+3b=0
4a-2=0
a=1/2
2(2a+3b)²-3(2a+3b)+8(2a+3b)²-7(2a+3b)
=10(2a+3b)²-10(2a+3b)
将a=1/2,b=-2/3代入原式中,得
=10(1-2)²+10(1-2)
=10-10
=0