原式=[x(x+y)/x(x-y)]÷(x+y)÷[-xy/y(y-x)]
=[(x+y)/(x-y)]×[1/(x+y)]×[(x-y)/x]
=[(x+y)(x-y)]/[x(x-y)(x+y)]
=1/x
初一分式运算3化简x^2+xy/x^2-xy÷（x+y)÷ -xy/y^2-xy的结果是________________
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