In(x/2)立方根-In(y/2)立方根
=1/3(ln(x/2)-ln(y/2))
=1/3*(lnx-ln2-lny+ln2)
=1/3*(lnx-lny)
=a/3
若Inx-Iny=a,则In(x/2)立方根-In(y/2)立方根等于--------
In(x/2)立方根-In(y/2)立方根
=1/3(ln(x/2)-ln(y/2))
=1/3*(lnx-ln2-lny+ln2)
=1/3*(lnx-lny)
=a/3