下面各题怎样简便就怎样算.[9/11]-([9/2]+[3/1])[6/5]+[8/5]+[6/1]+[8/3]8-[1

1个回答

  • 解题思路:(1)先算括号里的加法,再算外边的减法;

    (2)按从左到右的运算顺序计算;

    (3)根据减法的性质计算;

    (4)根据减法的性质计算.

    (1)[9/11]-([9/2]+[3/1])

    =[9/11]-[15/2]

    =-[147/22]

    (2)[6/5]+[8/5]+[6/1]+[8/3]

    =[6/5]+[8/5]+[6/1]+[8/3]

    =[14/5]+6+2[2/3]

    =8[4/5]+2[2/3]

    =11[7/15]

    (3)8-[16/5]-[16/11]

    =8-([16/5]+[16/11])

    =8-4[36/55]

    =3[19/55]

    (4)[10/9]-([6/5]-[5/3])

    =[10/9]+[5/3]-[6/5]

    =[25/9]-[6/5]

    =[71/45]

    点评:

    本题考点: 分数的加法和减法;运算定律与简便运算.

    考点点评: 计算四则混合运算时,要按照运算顺序,先算乘除,后算加减,有括号的先算括号里面的,再算括号外面的.能简算的要简算.