计算:m−m2m2−1÷mm−1•(−m+1m−1)2.
1个回答
原式=
m(1−m)
(m+1)(m−1)÷
m
m−1•
(m+1)2
(m−1)2
=
−m(m−1)
(m+1)(m−1)•
m−1
m•
(m+1)2
(m−1)2
=−
m+1
m−1.
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