Question

当A为何值时,(a-1)x^2+2ax+2a-2=0有两个不相等的实数根

Answer 1

当a-1=0,即a=1时,原方程为2x+2-2=0,x=0.

所以a≠1

则△=4a^2-4(a-1)(2a-2)=4a^2-8(a^2-2a+1)=-4a^2+16a-8>0

即a^2-4a+2