y=sin(-2x+π/3)
=sin[π-(-2x+π/3)]
=sin(2x+2π/3)
=sin2(x+π/3)
先将y=sinx x轴上所有横坐标点缩短为原来的1/2得y=sin2x再将所得到的图像向左平移π/3个单位得到所求图像y=sin2(x+π/3)即y=sin(-2x+π/3)
y=sin(-2x+π/3)
=sin[π-(-2x+π/3)]
=sin(2x+2π/3)
=sin2(x+π/3)
先将y=sinx x轴上所有横坐标点缩短为原来的1/2得y=sin2x再将所得到的图像向左平移π/3个单位得到所求图像y=sin2(x+π/3)即y=sin(-2x+π/3)