Question

tan(π/4-x)=√3-2,tanx=?

Answer 1

tan(π/4-x)=(1-tanx)/(1+tanx)=√3-2

1-tanx=√3-2+(√3-2)tanx

0=√3-3+(√3-1)tanx

tanx=(3-√3)/(√3-1)=(3-√3)(√3+1)/2=2√3/2