∵a=b×(2/3)=c+(1/5)=d-(1/12)
∴b=(3/2)a
c=a-(1/5)
d=a+(1/12)
∴b、d大于a大于c
∵a,b,c,d都大于1
∴b-d=(3/2)a-a-(1/12)=(1/2)a-1/12>0
∴b>d
∴b>d>a>c
∵a=b×(2/3)=c+(1/5)=d-(1/12)
∴b=(3/2)a
c=a-(1/5)
d=a+(1/12)
∴b、d大于a大于c
∵a,b,c,d都大于1
∴b-d=(3/2)a-a-(1/12)=(1/2)a-1/12>0
∴b>d
∴b>d>a>c