如图,AB是圆O的直径,点P在AB的延长线上,弦CE交AB于点D,连结OE,AC,已知∠POE=2∠CAB,∠P=∠E.

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  • 连接AE

    ∠POE=∠OAE ∠OEA=2∠OAE

    ∠POE=2∠CAB

    ∠OAE=∠CAB

    弧BC=弧BE

    AB是直径

    CE⊥AB

    (2)连接OC

    ∠P=∠E=∠OCE

    ∠P ∠PCD=90°

    ∠P ∠OCE=90°

    PC是切线

    (3)PC²=PB×PA=9(9 6x)

    设OD=x,BD=2x,AB=6x

    DC²=2x×4x=8x²

    PC²=CD² PD²=8x² (9 2x)²

    9(9 6x)=8x² (9 2x)²

    x=1.5

    半径=3x=4.5

    tan∠APC=CD/PD=√2/4

    =∠∠∠