Question

16分之一(2a+1)(2a-1)(a^4+16分之一)(4a^2+1)

Answer 1

1/16*(2a+1)(2a-1)(a^4+1/16)(4a^2+1)

=(1/16)*(a^4+1/16)(4a^2+1)(4a^2-1)

=(1/16)*(a^4+1/16)(16a^4-1)

=(a^4+1/16)(a^4-1/16)

=a^8-1/256