在实数范围内因式分解:(11)3x^2-4x-1(12)x^2-3x-9/4(13)2y^2-6y-3(14)-4a^2

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  • (11)3x^2-4x-1

    3x^2-4x-1

    =3(x^2-4/3x-1/3)

    令x^2-4/3x-1/3=0

    解得:x=(2±√7)/3

    即:3x^2-4x-1

    =3(x^2-4/3x-1/3)

    =3[x-(2+√7)/3][x-(2-√7)/3]

    (12)x^2-3x-9/4

    令x^2-3x-9/4=0

    解得:x=(3±3√2)/2

    即:x^2-3x-9/4

    =[x-(3+3√2)/2][x-(3-3√2)/2]

    (13)2y^2-6y-3

    2y^2-6y-3

    =2(y^2-3y-3/2)

    令:y^2-3y-3/2=0

    解得;y=(3±2√3)/2

    即:2y^2-6y-3

    =2(y^2-3y-3/2)

    =2[y-(3+2√3)/2][y-(3-2√3)/2]

    (14)-4a^2+6a+3

    -4a^2+6a+3

    = -4(a^2-3/2-3/4)

    令a^2-3/2-3/4=0

    解得:a=(3±√21)/4

    即;-4a^2+6a+3

    =-4[a-(3+√21)/4][a-(3-√21)/4]

    (15)9y^2-6xy-x^2

    9y^2-6xy-x^2

    =9(y^2-2/3xy-1/9x^2)

    令y^2-2/3xy-1/9x^2=0

    解得:y=(3±3√2)/9 x

    即:9y^2-6xy-x^2

    =9(y^2-2/3xy-1/9x^2)

    =9[y-(3+3√2)/9 x][y-(3-3√2)/9 x]

    (16)-2x^2+7xy-4y^2

    -2x^2+7xy-4y^2

    =-2(x^2-7/2xy+2)

    解得:x=(7±√17)/4 y

    即:2x^2+7xy-4y^2

    =-2(x^2-7/2xy+2)

    = - 2[x-(7+√17)/4 y][x-(7-√17)/4 y]

    (17)4x^2-4xy-y^2

    4x^2-4xy-y^2

    =4(x^2-xy-1/4y^2)

    解得:x=(1±√2x)/2 y

    4x^2-4xy-y^2

    =4(x^2-xy-1/4y^2)

    =4[x-(1+√2)/2 y][x-(1-√2)/2 y]

    =[2x-(1+√2) y][2x-(1-√2) y]

    (18)1/2x^4-5/2x^2+3

    1/2x^4-5/2x^2+3

    =1/2(x^4-5x^2+6)

    =1/2(x-2)(x-3)

    (19)2x^3+3x^2-2x

    2x^3+3x^2-2x

    =2x(x^2+3/2x-1)

    =2x(x-1/2)(x+2)

    (20)y^4-9y^2+8

    y^4-9y^2+8

    =(y^2-8)(y^2-1)

    =(y-2√2)(y+2√2)(y-1)(y+1)

    (21)3x^4-6x^3+2x^2

    3x^4-6x^3+2x^2

    =3x^2(x^2-2x+2/3)

    令x^2-2x+2/3=0

    解得:x=1±√3/3

    即:3x^4-6x^3+2x^2

    =3x^2(x^2-2x+2/3)

    =3x^2[x-(1+√3/3)][x-(1-√3/3)]

    (22)3x^2-2x-2

    3x^2-2x-2

    =3(x^2-2/3x-2/3)

    令x^2-2/3x-2/3=0

    解得:x=(1±√7)/3

    即:3x^2-2x-2

    =3(x^2-2/3x-2/3)

    =3[x-(1+√7)/3][x-(1-√7)/3]

    (23)2a^2-4ab-5b^2

    2a^2-4ab-5b^2

    =2(a^2-2ab-5/2b^2)

    令a^2-2ab-5/2b^2=0 【把b看成常数】

    解得:a=(2±√14)/2 b

    即:2a^2-4ab-5b^2

    =2(a^2-2ab-5/2b^2)

    =2[x-(2-√14)/2 b][x-(2+√14)/2 b]

    (24)-3x^2+4xy+10y^2

    -3x^2+4xy+10y^2

    =-3(x^2-4/3xy-10/3y^2) 【把y当做常数】

    令x^2-4/3xy-10/3y^2=0

    解得:x=(2±√34)/3 y

    即::-3x^2+4xy+10y^2

    =-3(x^2-4/3xy-10/3y^2)

    =-3[x-(2+√34)/3 y][x-(2-√34)/3 y]

    (25)4x^2+12x+3

    4x^2+12x+3

    =4(x^2+3x+3/4)

    令x^2+3x+3/4=0

    解得:x=(-3±√6)/2

    即:4x^2+12x+3

    =4(x^2+3x+3/4)

    =4[x-(-3+√6)/2][x-(-3-√6)/2]

    =(2x+3-√6)(x+3+√6)