Question

在三角形ABC中,三边长分别为a,b,c已知a=m,b=1/2(m^2-1),c=1/2(m^2+1)求证三角形ABC为

Answer 1

2c=m^2+1

2b=m^2-1

(2c)^2-(2b)^2=(2c+2b)(2c-2b)

=2m^2*2

=4m^2

所以c^2-b^2=m^2=a^2

a^2+b^2=c^2

所以是直角三角形