(a+1)(b+1)=ab+(a+b)+1=8
(a-1)(b-1)=ab-(a+b)+1=0,得到a=1,b=3或者a=3,b=1
(a-1)/(a+1)=(a-1)(b+1)/(a+1)(b+1)=(a-1)(b+1)/8
同理(b-1)/(b+1)=(b-1)(a+1)/8
则(a-1)/(a+1)=0或者0.5
(a+1)(b+1)=ab+(a+b)+1=8
(a-1)(b-1)=ab-(a+b)+1=0,得到a=1,b=3或者a=3,b=1
(a-1)/(a+1)=(a-1)(b+1)/(a+1)(b+1)=(a-1)(b+1)/8
同理(b-1)/(b+1)=(b-1)(a+1)/8
则(a-1)/(a+1)=0或者0.5