Question

已知函数x,y满足x≥1,y≥1loga^2(x)+loga^2（y）=loga(x^2/a)+loga(y^2/a^1

Answer 1

loga^2(xy)=loga(x^2/a*y^2/a^16)

1/2*loga(xy)=loga[(xy)^2/a^17]

xy=(xy)^4/a^34

(xy)^3=a^34

所以loga(xy)=loga[a^(34/3)]=34/3