Question

恒温下,将amol N2与bmol H2的混合气体通入一个固定容积的密闭容器中,发生如下反应:N2(g)+3H2(g)2

Answer 1

(1) a=13+6/2 =16

(2)NH3的物质的量=716.8*25%/22.4 =8mol

(3)n(平衡)=716.8/22.4 =32mol

n(始) =32+8/2 + 8*3/2 - 8 =40mol

n(始):n(平)=40/32=5:4

(4)原混合气体中,a:b= 16/(40-16) =2:3

(5)达到平衡时N2和H2的转化率之比a(N2):a(H2)=4/16 :12/24 =1:2

(6)平衡混合气体中,n(N2):n(H2):n(NH3)= (16-4):(24-12):8=3:3:2